Check if Array Is Sorted and Rotated
Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero).
Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return false.
There may be duplicates in the original array.
Note: An array A rotated by x positions results in an array B of the same length such that B[i] == A[(i+x) % A.length] for every valid index i.
Example 1
Input: nums = [3,4,5,1,2]
Output: true
Explanation: [1,2,3,4,5] is the original sorted array. You can rotate the array by x = 3 positions to begin on the element of value 3: [3,4,5,1,2].
Example 2
Input: nums = [2,1,3,4]
Output: false
Explanation: There is no sorted array once rotated that can make nums.
Example 3
Input: nums = [1,2,3]
Output: true
Explanation: [1,2,3] is the original sorted array. You can rotate the array by x = 0 positions (i.e. no rotation) to make nums.
Constraints
- 1 <= nums.length <= 100
- 1 <= nums[i] <= 100
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