Find and Replace Pattern
Given a list of strings words and a string pattern, return a list of words[i] that match pattern.
Given a list of strings words and a string pattern, return a list of words[i] that match pattern. You may return the answer in any order.
A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word.
Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.
Example 1
Input: words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb"
Output: ["mee","aqq"]
Explanation: "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}. "ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation, since a and b map to the same letter.
Example 2
Input: words = ["a","b","c"], pattern = "a"
Output: ["a","b","c"]
Constraints
- 1 <= pattern.length <= 20
- 1 <= words.length <= 50
- words[i].length == pattern.length
- pattern and words[i] are lowercase English letters.
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