How Many Numbers Are Smaller Than the Current Number
Given the array nums, for each nums[i] find out how many numbers in the array are smaller than it.
Given the array nums, for each nums[i] find out how many numbers in the array are smaller than it. That is, for each nums[i] you have to count the number of valid j's such that j != i and nums[j] < nums[i].
Return the answer in an array.
Example 1
Input: nums = [8,1,2,2,3]
Output: [4,0,1,1,3]
Explanation: For nums[0]=8 there exist four smaller numbers than it (1, 2, 2 and 3). For nums[1]=1 does not exist any smaller number than it. For nums[2]=2 there exist one smaller number than it (1). For nums[3]=2 there exist one smaller number than it (1). For nums[4]=3 there exist three smaller numbers than it (1, 2 and 2).
Example 2
Input: nums = [6,5,4,8]
Output: [2,1,0,3]
Example 3
Input: nums = [7,7,7,7]
Output: [0,0,0,0]
Constraints
- 2 <= nums.length <= 500
- 0 <= nums[i] <= 100
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