Longest Substring of One Repeating Character
You are given a 0-indexed string s.
You are given a 0-indexed string s. You are also given a 0-indexed string queryCharacters of length k and a 0-indexed array of integer indices queryIndices of length k, both of which are used to describe k queries.
The ith query updates the character in s at index queryIndices[i] to the character queryCharacters[i].
Return an array lengths of length k where lengths[i] is the length of the longest substring of s consisting of only one repeating character after the ith query is performed.
Example 1
Input: s = "babacc", queryCharacters = "bcb", queryIndices = [1,3,3]
Output: [3,3,4]
Explanation: - 1st query updates s = "bbbacc". The longest substring consisting of one repeating character is "bbb" with length 3. - 2nd query updates s = "bbbccc". The longest substring consisting of one repeating character can be "bbb" or "ccc" with length 3. - 3rd query updates s = "bbbbcc". The longest substring consisting of one repeating character is "bbbb" with length 4. Thus, we return [3,3,4].
Example 2
Input: s = "abyzz", queryCharacters = "aa", queryIndices = [2,1]
Output: [2,3]
Explanation: - 1st query updates s = "abazz". The longest substring consisting of one repeating character is "zz" with length 2. - 2nd query updates s = "aaazz". The longest substring consisting of one repeating character is "aaa" with length 3. Thus, we return [2,3].
Constraints
- 1 <= s.length <= 10^5
- s consists of lowercase English letters.
- k == queryCharacters.length == queryIndices.length
- 1 <= k <= 10^5
- queryCharacters consists of lowercase English letters.
- 0 <= queryIndices[i] < s.length
Hints
Companies
No companies reported yet.
Discussion
Sign in to join the discussion.
Loading discussion...
Test results
No test cases yet.