Match Substring After Replacement
You are given two strings s and sub.
You are given two strings s and sub. You are also given a 2D character array mappings where mappings[i] = [oldi, newi] indicates that you may perform the following operation any number of times:
Each character in sub cannot be replaced more than once.
Return true if it is possible to make sub a substring of s by replacing zero or more characters according to mappings. Otherwise, return false.
A substring is a contiguous non-empty sequence of characters within a string.
Example 1
Input: s = "fool3e7bar", sub = "leet", mappings = [["e","3"],["t","7"],["t","8"]]
Output: true
Explanation: Replace the first 'e' in sub with '3' and 't' in sub with '7'. Now sub = "l3e7" is a substring of s, so we return true.
Example 2
Input: s = "fooleetbar", sub = "f00l", mappings = [["o","0"]]
Output: false
Explanation: The string "f00l" is not a substring of s and no replacements can be made. Note that we cannot replace '0' with 'o'.
Example 3
Input: s = "Fool33tbaR", sub = "leetd", mappings = [["e","3"],["t","7"],["t","8"],["d","b"],["p","b"]]
Output: true
Explanation: Replace the first and second 'e' in sub with '3' and 'd' in sub with 'b'. Now sub = "l33tb" is a substring of s, so we return true.
Constraints
- 1 <= sub.length <= s.length <= 5000
- 0 <= mappings.length <= 1000
- mappings[i].length == 2
- oldi != newi
- s and sub consist of uppercase and lowercase English letters and digits.
- oldi and newi are either uppercase or lowercase English letters or digits.
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