hardArrayBinary SearchGreedy 0 views

Maximize the Distance Between Points on a Square

You are given an integer side, representing the edge length of a square with corners at (0, 0), (0, side), (side, 0), and (side, side) on a Cartesian plane.

You are given an integer side, representing the edge length of a square with corners at (0, 0), (0, side), (side, 0), and (side, side) on a Cartesian plane.

You are also given a positive integer k and a 2D integer array points, where points[i] = [xi, yi] represents the coordinate of a point lying on the boundary of the square.

You need to select k elements among points such that the minimum Manhattan distance between any two points is maximized.

Return the maximum possible minimum Manhattan distance between the selected k points.

The Manhattan Distance between two cells (xi, yi) and (xj, yj) is |xi - xj| + |yi - yj|.

Example 1

Input: side = 2, points = [[0,2],[2,0],[2,2],[0,0]], k = 4

Output: 2

Explanation: Select all four points.

Example 2

Input: side = 2, points = [[0,0],[1,2],[2,0],[2,2],[2,1]], k = 4

Output: 1

Explanation: Select the points (0, 0) , (2, 0) , (2, 2) , and (2, 1) .

Example 3

Input: side = 2, points = [[0,0],[0,1],[0,2],[1,2],[2,0],[2,2],[2,1]], k = 5

Output: 1

Explanation: Select the points (0, 0) , (0, 1) , (0, 2) , (1, 2) , and (2, 2) .

Constraints

  • 1 <= side <= 10^9
  • 4 <= points.length <= min(4 * side, 15 * 10^3)
  • points[i] == [xi, yi]
  • The input is generated such that: points[i] lies on the boundary of the square. All points[i] are unique.
  • points[i] lies on the boundary of the square.
  • All points[i] are unique.
  • 4 <= k <= min(25, points.length)

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