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Maximum Number of Groups With Increasing Length

You are given a 0-indexed array usageLimits of length n.

You are given a 0-indexed array usageLimits of length n.

Your task is to create groups using numbers from 0 to n - 1, ensuring that each number, i, is used no more than usageLimits[i] times in total across all groups. You must also satisfy the following conditions:

Return an integer denoting the maximum number of groups you can create while satisfying these conditions.

Maximum Number of Groups With Increasing Length diagram

Example 1

Input: usageLimits = [1,2,5]

Output: 3

Explanation: In this example, we can use 0 at most once, 1 at most twice, and 2 at most five times. One way of creating the maximum number of groups while satisfying the conditions is: Group 1 contains the number [2]. Group 2 contains the numbers [1,2]. Group 3 contains the numbers [0,1,2]. It can be shown that the maximum number of groups is 3. So, the output is 3.

Example 2

Input: usageLimits = [2,1,2]

Output: 2

Explanation: In this example, we can use 0 at most twice, 1 at most once, and 2 at most twice. One way of creating the maximum number of groups while satisfying the conditions is: Group 1 contains the number [0]. Group 2 contains the numbers [1,2]. It can be shown that the maximum number of groups is 2. So, the output is 2.

Example 3

Input: usageLimits = [1,1]

Output: 1

Explanation: In this example, we can use both 0 and 1 at most once. One way of creating the maximum number of groups while satisfying the conditions is: Group 1 contains the number [0]. It can be shown that the maximum number of groups is 1. So, the output is 1.

Constraints

  • 1 <= usageLimits.length <= 10^5
  • 1 <= usageLimits[i] <= 10^9

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