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Square Every Element In Place

Practice raw array basics: fixed-size indexing, iteration, and in-place mutation.

Given an array of integers nums, replace each element with its square, modifying the array in place, and return it.

This is a basics exercise for raw arrays specifically (not a dynamic list): the point is index-based access and mutation, nums[i] = ..., which is the one operation a fixed-size array gives you that a dynamic list's higher-level API can obscure.

Example 1

Input: nums = [1,-2,3]

Output: [1,4,9]

Example 2

Input: nums = [0,5]

Output: [0,25]

Example 3

Input: nums = []

Output: []

Constraints

0 <= nums.length <= 1000
-100 <= nums[i] <= 100

Follow-up

Could you do this without an explicit index variable? What would you lose by doing so?

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class Solution {
    public int[] squareInPlace(int[] nums) {
        // your code here
        return nums;
    }
}

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